7x^2+58x=0

Solution for 7x^2+58x=0 equation:

7x^2+58x=0

a = 7; b = 58; c = 0;
Δ = b2-4ac
Δ = 582-4·7·0
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-58}{2*7}=\frac{-116}{14}
=-8+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+58}{2*7}=\frac{0}{14}
=0
$